Question

найдите разность 1/8х- 7х+у/8ху

Answer 1

$\mathtt{ \dfrac{1}{8}x-7x+\dfrac{y}{8xy}= \dfrac{x^2y-7x^2y+8xy^2}{8xy}=\dfrac{yx(x-7x+8y)}{8xy}= \dfrac{-6x+8y}{8xy}=}\\\mathtt{= \dfrac{-2(3x-4y)}{8xy}= \boxed{-\dfrac{3x-4y}{4xy}} }$