Question

найдите частное а^2 - 81/а^2 - 12а - 36 : а^2 - 9а/а - 6

Answer 1

$\frac{a^{2} -81}{a^{2} -12a-36}: \frac{a^{2} -9a}{a-6}= \frac{(a-9)(a+9)}{(a-6)^{2} }* \frac{a-6}{a(a-9)}= \frac{a+9}{a(a-6)}$