Question

((a^7/5)/(a^7/8))^40, при а 2^корень из 6

Answer 1

$(frac{a^{frac{7}{5}}}{a^{frac{7}{8}}})^{40}=frac{a^{frac{7}{5}*40}}{a^{frac{7}{8}*40}}=frac{a^{56}}{a^{35}}=a^{56-35}=a^{21};~[a=2^{sqrt{6}}]~(2^{sqrt{6}})^{21}=\(2^{20})^{sqrt{6}}*2^{sqrt{6}}=(1024^2)^{sqrt{6}}*2^{sqrt{6}}$