Question

уравнение:
x^4-4x^2+4=0

Answer 1

$x^4-4x^2+4=0 \\(x^2)^2-2*2*x^2+2^2=0 \\(x^2-2)^2=0 \\x^2-2=0 \\x^2=2 \\x_1=\sqrt{2} \\x_2=-\sqrt{2}$
Ответ: $x_1=\sqrt{2}; \ x_2=-\sqrt{2}$

Answer 2

x^4-4x^2+4=0

(X^2)^2 - 2*2*X^2 + 2^2 = 0

(X^2 – 2)^2 = 0

X^2 – 2 = 0

X^2 = 2

X1 = √2

X2 = -√2