Question

Графические найдите корни
1) икс квадрат +x-12>0
2) 2
— - 2>0
X

Answer 1

$x^{2} + x-12\ \textgreater \ 0 \\ \left \{ {{ x_{1}+ x_{2}\ \textgreater \ -1 } \atop { x_{2}*x_{1} \ \textgreater \ -12}} \right. \\ \left \{ {{ x_{1} \ \textgreater \ 3} \atop { x_{2}\ \textgreater \ -4 }} \right. \\ (-4;3)$