Предмет: Математика, автор: Санёк126

В прямоугольным треугольнике один из углов равен 40 градусов. Найдите внешний угол при вершине второго острого угла. Ответ дайте в градусах

Ответы

Автор ответа: Liza08082008

Сумма углов треугольника равна 180 градусов
уголА=90 градусов
уголБ=х градусов- вершина
уголС=40 градусов
Угол Б=180-(90+40)=50 градусов
Найдем уголС внешний
180-40=140 градусов

Санёк126: спс

Автор ответа: sedinalana

ΔABC,<C=90,<A=40
<A+<B=90⇒<B=90-40=50
<A внешний угол при вершине А вместе 180гр,значит внешний равен 180-40=140
<В внешний угол при вершине В вместе 180гр,значит внешний равен 180-50=130

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