Question

cos(n/2 + x)=0
tg^2 x = tgx

Answer 1

1)cospi/2+x=0
arccos0=pi/2+pi*k,k∈z
1.pi/2+x=pi/2
x1=0+2pi*k,k∈z
2.pi/2+x=3pi/2
x=pi+2pi/n,n∈z
Ответ:x1=0+2πk,k∈z
x2=π+2πn,n∈z
tg^2x=tgx
]tgx=y
y^2=y
y^2-y=0
y(y-1)=0
y=0 y=1
tgx=0
x=0+pi*k,k∈z
tgx=1
x=pi/4+2pi*n,n∈z
Ответ:x1=0+pi*k,k∈z;x2=pi/4+2pi*n,n∈z