Question

(8¹¹×32-²)³
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8^7

Answer 1

$displaystyle (8^{11}*32^{-2})^{3}:8^{7}=((2^{3})^{11}*(2^{5})^{-2})^{3}*(2^{3})^{-7}= \ \ =2^{99}*2^{-30}*2^{-21}=2^{48}$