Question

Найти производную функцию:
1) 2x^3-3x^2+6x+1=

2) (x^2-x)'(x^3+x)=

Answer 1

1) y' = 6x²-6x+6
2) y' = (x²-x)' * (x³+x) + (x²-x)*(x³+x)' = (2x-1)(x³+x) + (x²-x)(3x²+1) = 
= 2x^4 +2x²-x³-x+3x^4+x²-3x³-x = 5x^4 -4x³+3x²-2x