Предмет: Алгебра, автор: alekscj

Найдите область определения функции:
y = log4 (3x+1)/(1-3x)

Ответы

Автор ответа: Gerren

0

(3x+1)/(1-3x)>0
1-3x≠0 x≠1/3
(3x+1)/(1-3x)>0
- -1/3 + 1/3 -
D(y)=(-1/3,1/3)

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