Question

решите уравнение

(2x-1) (x+4)-2(x+3)(x-2)=10

Answer 1

(2x-1)(x+4)-2(x+3)(x-2)=10
2x²+8x-x-4-2(x²-2x+3x-6)=10
2x²+7x-4-2(x²+x-6)=10
2x²+7x-4-2x²-2x+12=10
5x+8=10
5x=2
x=2/5
x=0,4
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Answer 2

$(2x-1)(x+4)-2(x+3)(x-2)=10\\2x^2+7x-4-2(x^2+x-6)=10\\2x^2+7x-14-2x^2-2x+12=0\\5x-2=0\\x=0,4$