Question

можно подробное решение?

Answer 1

$\left \{ {{(x+8)^2+(y-4)^2=50} \atop {y-x=2}} \right. \; ,\; \left \{ {{(x+8)^2+(x-2)^2=50} \atop {y=x+2}} \right. \; ,\\\\x^2+16x+64+x^2-4x+4=50\\\\2x^2+12x+18=0\; |:2\\\\x^2+6x+9=0\\\\(x+3)^2=0\; \; \Rightarrow \; \; x+3=0\; ,\; \; x=-3\\\\y=x+2=-3+2=-1\\\\5(x+y)=5(-3-1)=-20\\\\Otvet:\; \; (-3,-1)\; \; ,\; \; -20.$