Question

Как это решить? Помогите пожалуйста!
((u+1)^2/64−64u^3):(1−u^2(8u−8)^2)

Answer 1

$\frac{(u+1)^{2}}{64-64u^{3}}: \frac{1- u^{2} }{(8u-8)^{2}} = \frac{(u+1)(u+1)}{64(1-u)(1+u+u^{2})} * \frac{8^{2}(u-1)(u-1)}{(1-u)(1+u)}= \\ \\ \frac{(u+1)(u-1)}{-(1-u)(1+u+u^{2})}= \frac{(u+1)(u-1)}{(u-1)(1+u+u^{2})} = \frac{u+1}{1+u+u^{2}}$