Предмет: Математика, автор: rznden2010

Доброго времени суток, помогите решить производную y=sin^2x/sinx^2

Ответы

Автор ответа: IrkaShevko
1
y' = (2sinxcosx * sinx² - sin²x * 2xcosx²)/sin²x²

(u/v)' = (u'v - uv')/v²
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