Question

вычислить 2sinn/6-3cos(-n/3)

Answer 1

$2sin \frac{ \pi }{6} -3cos(- \frac{ \pi }{3} )=2sin \frac{ \pi }{6} -3cos\frac{ \pi }{3}=2* \frac{1}{2} -3* \frac{1}{2} =- \frac{1}{2}$

Answer 2

2*sin(π/6)-3*cos(-π/3)=2*(1/2)-3*(1/2)=1-1,5=-0,5.