Question

Предел функции
$\lim_{x \to \infty} 6x+3/3x-2$

Answer 1

$\lim_{x \to \infty} \frac{6x+3}{3x-2} = \lim_{x \to \infty} \frac{ \frac{6x}{x}+ \frac{3}{x} }{ \frac{3x}{x}- \frac{2}{x} } = \lim_{x \to \infty} \frac{6+ \frac{3}{x} }{3- \frac{2}{x} } = \frac{6}{3} =2$