Question

обчислити.
27^2/3+4^0
8^1/3-2^0

Answer 1

$27^{ \frac{2}{3}} -4^0= \sqrt[3]{27} ^2 -1=3^2 -1=9-1 =8$
$8^{\frac{1}{3}}-2^0=2-1=1$