Question

Найти производную функции:
(3-5x)/x^2-cos(log5x)

Answer 1

$y' = \frac{(3-5x)'*x^2-(3-5x)*(x^2)'}{(x^2)^2} + sin(log_5x)*(log_5x)'=\\ = \frac{-5x^2-6x+10x^2}{x^4} + \frac{sin(log_5x)}{xln5} =\\ =\frac{5x-6}{x^3} + \frac{sin(log_5x)}{xln5}$