Question

$(frac{2}{3})^2^x* (frac{9}{16})^2^x= frac{3}{8}$

Answer 1

$( frac{2}{3} )^{2x}*( frac{9}{16} )^{2x}= frac{3}{8} \ \ ( frac{2}{3} *frac{9}{16} )^{2x}= frac{3}{8} \ \ ( frac{3}{8} )^{2x}= (frac{3}{8})^1 \ \ 2x=1 \ x=0.5$

Answer 2

спасибо