Question

Помогите решить.
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1. (y + 4)(4 - y) + (y + 5)y > 6y - 20
2. (3x + 2)$^{2}$ - (4 - 3x)$^{2}$ $leq$ 14 + 37x
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Answer 1

1
16-y²+y²+5y-6y+20>0
y<36
y∈(-∞;36)
2
9x²+12x+4-16+24x-9x²-14-37x≤0
x≥-26
x∈[-26;∞)