Question

(5-х)^2-(3х-2)*(2х+1)=х*(2-5х)

Answer 1

$(5-x)^2-(3x-2)*(2x+1)=x*(2-5x)\ 25-10x+x^2-(6x^2+3x-4x-2)=2x-5x^2\ 25-10x+x^2-6x^2-3x+4x+2-2x+5x^2=0\ 25-10x-3x+4x+2-2x=0\ -11x=-27\ x= frac{27}{11} =2 frac{5}{11}$