Question

10sin^2x-6sin2x-11cos^2x=1

Answer 1

10sin²x-12sinxcosx-11cos²x-sin²x-cos²x=0
9sin²x-12sinxcosx-12cos²x=0/3cos²x
3tg²x-4tgx-4=0
tgx=a
3a²-4a-4=0
D=16+48=64
a1=(4-8)/6=-2/3⇒tgx=-2/3⇒x=-arctg2/3+πk,k∈z
a2=(4+8)/6=2⇒tgx=2⇒x=arctg2+πk,k∈z