Question

решите ✓3-2✓3sin^2 11π/12

Answer 1

√3-2√3*(1-cos11π/6)/2=√3-√3*(1-cos(2π-π/6))=√3-√3(1-cosπ/6)=
=√3-√3+√3*√3/2=3/2=1,5