Question

помогите решить весь второй вариант

Answer 1

1) = log_{15} (5*3) = log_{15}15 = 1;
3) = log_{5}( frac{50}{2} ) = log_{5}25 = 2; 
4) = [tex] log_{3} ( frac{ frac{1}{6} }{ frac{81}{2} } ) = log_{3} frac{1}{243} = log_{3} 3^{- 5} =- 5;  
2)  =  log_{0,1} (5*2) = log_{0,1} 10 = log_{0,1} 10^{-1} = -1; 
6)  = [tex] log_{13} ( 13^{ frac{2}{5} } ) = frac{2}{5};
5)  = [tex] log_ 2 2^{3*7} = 2^{21} =21;