Question

тождество (1+sin(3Pi/2-6A))*tg(Pi/2-3A)=sin6A
Умоляяяю,помогите!

Answer 1

(1+sin(3π/2-6A))*tg(π/2-3A)=(1-cos6A)*ctg3A=
=(sin²3A+cos²3A-cos²3A+sin²3A)*cos3A/sin3A=2sin²3A*cos3A/sin3A=sin6A
sin6A=sin6A