Question

$2log_32-log_3(x-1)=1+log_35$

Answer 1

2㏒₃2- ㏒₃(х-1)=1 +㏒₃5               ОДЗ х-1>0  x>1

㏒₃2² =  ㏒₃3 +㏒₃5 +㏒₃(х-1)

 ㏒₃4= ㏒₃3*5*(х-1)

4=15х-15

15х=19

х=19/15 = 1 4/15

Answer 2

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