Question

помогите пожжжаааллууййсстта

Answer 1

3) (2sinA+sin2A)/(2sinA-sin2A) = (2sinA+2sinAcosA)/(2sinA-2sinAcosA) = (2sinA(1+cosa))/(2sina(1-cosa)) = (1+cosa)/(1-cosa) = (1+1/2)/(1-1/2) = 3/2/1/2 = 3