Question

решите способом подстановки:
{3х+1=8у
{11у-3х=-11

Answer 1

$left { {{3x=8y-1} atop {11y-(8y-1)=-11}} right. left { {{3x=8y-1} atop {11y-8y+1=-11}} right. left { {{3x=8y-1} atop {3y=-12}} right. left { {{3x=8y-1} atop {y=-4}} right. left { {{3x=8*(-4)-1} atop {y=-4}} right.$

3х=-33=>х=-11
у=-4

Answer 2

а "х"?

Answer 3

Снизу написано