Предмет: Физика, автор: Анастасия5867

На концах рычага, действуют силы 50Н и 250Н. Расстояние от точки опоры до точки приложения меньшей силы равно 12см. Определите длину рычага

Ответы

Автор ответа: fatt52

F1=50 H F2=250 H L1=12 см L=?
===
F1*L1=F2*L2
L2=L-L1
F1*L1=F2*(L-L1)
L=L1*(F1+F2)/F2=12*(50+250)/250=14.4 см
====================================

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