Question

Решите пж по алгебре один небольшой пример))

Answer 1

(b/(b-c)+bc/(c²-b²))*((c²-2bc+b²)/b²)=(-b/(c-b)+bc/((c-b)(c+b))*((c-b)/b²)=
=((-b(b+c)+bc)/(c²-b²))*((c-b)²/b²)=((-b²-bc+bc)/(c²-b²))*((c-b)²/b²)=
=-b²(c-b)²/((c-b)(c+b)b²)=-(c-b)/(c+b)=(b-c)/(b+c).