Question

12x^-9x-3=0 решить уравнение

Answer 1

$12 x^{2} -9x-3=0 \ a=12 b=-9 c=-3 \ D=b^{2}-4ac=(-9)^{2}-4*12*(-3)=81+144=225=15^{2} \ x_{1,2}= frac{9б15}{2*12} = left[begin{array}{c}1\ -frac{1}{4} end{array}right]$