Question

Интеграл sin10x^2 * xdx
Выручайте❤️

Answer 1

$int sin (10x^2) *xdx=frac{1}{20} int sin(10x^2)* (10*2x) dx=$
$frac{1}{20} *int sin(10x^2) d(10x^2)=$
$frac{1}{20}*(-cos 10x^2)+C=-frac{cos (10x^2)}{20}+C$, C є R