Question

$(x^{2} +x)^2+( x^{2} +x)-2=0$

Answer 1

$(x^2+x)^2+(x^2+x)-2=0; \ x^2+x=t; \ t^2+t-2=0; \ D=1+8=9; \ t_{1}= frac{-1-3}{2}=-2; \ t_{2}= frac{-1+3}{2}=1; \ x^2+x=-2; \ x^2+x+2=0; \ D=1-8=-7 textless 0; \ x^2+x=1; \ x^2+x-1=0; \ D=1+4=5; \ x_{1}= frac{-1- sqrt{5} }{2}; \ x_{2}= frac{-1+ sqrt{5} }{2}.$