Question

((3/9-х2)+(1/3-х)):х/х2-6х+9

Answer 1

$( frac{3}{9-x^{2}} + frac{1}{3-x} ) : frac{x}{x^{2}-6x+9} =$$( frac{3}{(3-x)(3+x)} + frac{1}{3-x} ) : frac{x}{(x-3)^{2}} =$$frac{3-(3+x)}{(3-x)(3+x)} : frac{x}{(x-3)^{2}} =$$frac{3-3-x}{(3-x)(3+x)} : frac{x}{(x-3)^{2}} =$$frac{-x}{(3-x)(3+x)} * frac{(-(3-x))^{2}}{x}} =$$frac{-1}{3+x} * 1 =$$frac{-1}{3+x}$