Question

$(\frac{x+3}{x-3} - \frac{x}{x+3}): \frac{x+1}{x+3}$

Answer 1

$.........= \frac{(x+3)(x+3)-x(x-3)}{(x-3)(x+3)}* \frac{x+3}{x+1}= \frac{ x^{2} +6x+9- x^{2} +3x}{(x-3)(x+1)} = \frac{9x+9}{(x-3)(x+1)}= \\ \\ \frac{9(x+1)}{(x-3)(x+1)} = \frac{9}{x-3}$