Question

Найдите значение выражения x^2-10x+25x-5 - x^2-36x+6 +x при x=2006

Answer 1

$dfrac{x^2 - 10x + 25}{x-5}- dfrac{x^2 - 36}{x+ 6} + x = dfrac{(x - 5)^2}{x-5} -dfrac{(x - 6)(x + 6)}{x + 6} + x = \ \ x - 5 - (x - 6) + x = 2x - 5 - x + 6 = x + 1 = 2006 + 1 = 2007$