Предмет: Химия, автор: tanyajana

К 6,5% раствору хлорида бария (ВаСl2 ) массой 80 г прилили избыток раствора серной кислоты. Вычислите массу выпавшего осадка.

Ответы

Автор ответа: Bedniy7Student

0

bacl 2 + h2so4 = baso4 + 2hcl

bacl2 = 0.065 x 80 = 5.2 / 208 = 0.025 m

0.025 x 233 (baso4 osadok) = 5.825 massa. otvet.

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