Question

x-1/x+2 + x+1/x-2 + 2x+8/4-x^2

Answer 1

$frac{x-1}{x+2} + frac{x+1}{x-2} + frac{2x+8}{4- x^{2} }= frac{x-1}{x+2} + frac{x+1}{x-2} - frac{2(x+4)}{(x-2)(x+2)} = \ \ frac{(x-1)(x-2)+(x+1)(x+2)-2(x+4)}{(x-2)(x+2)}= frac{ x^{2} -3x+2+ x^{2} +3x+2-2x-8}{(x+2)(x-2)}= frac{2 x^{2} -2x-4}{(x+2)(x-2)}$