Question

$3 sqrt5-4x=2-x$
2x-1/3x+4=x+7/x-1

Answer 1

$1), 3sqrt{5}-4x=2-x$
$3sqrt{5}-3x=2$
$-3x=2-3sqrt{5}$
$frac{-3x}{-3}=frac{2-3sqrt{5}}{-3}$
$x=frac{2-3sqrt{5}}{-3}$
$x=-frac{2-3sqrt{5}}{3}$
$x=-frac{1}{3}(2-3sqrt{5})$

$2), frac{2x-1}{3x+4}=frac{x+7}{x-1}$
$(2x-1)(x-1)=(x+7)(3x+4)$
$2x^2-3x+1=3x^2+25x+28$
$-x^2-28x-27=0$
$x^2+28x+27=0$
$D=b^2-4ac=28^2-4*1*27=784-108=676,, sqrt{676}=26$
$x_1=frac{-28+26}{2}=frac{-2}{2}=-1$
$x_2=frac{-28-26}{2}=frac{-54}{2}=-27$