Question

Помогите решить систему неравенств:
x^2-5x-14>0
x^2-2x-35<0

Answer 1

1) х²-5х-14 > 0
D = 25+56 = 81
x₁= 5-9 / 2 = -2
x₂= 5+9 / 2 = 7
   
    +         -         +
--------₀--------₀------->x
\\\ -2       7 /////////

2) х²-2х-35 < 0
D = 4+140 = 144
x₁ = 2-12 / 2 = -5
x₂ = 2+12 / 2 = 7
    
     +           -           +
----------₀---------₀-------->x
          -5 //////// 7


\\\\\\\ -2                  7 /////////
------₀---------₀----------------₀------->x
      -5 \\\\\\\\\\\ 7

x∈(-5; -2)