Question

найти производную
y=$frac{^x}{^x+1}$

Answer 1

$y'=( frac{x}{x+1} )'= frac{x'(x+1)-(x+1)'x}{(x+1)^2} = frac{x+1-x}{(x+1)^2} = frac{1}{(x+1)^2}$