Question

8х(1,4х+13,6у)+13х(0,8х-0,6у)=?
Если х=1 и у=1

Answer 1

$8x(1,4x+13,6y)+13x(0,8x-0,6y)=? ; x=1;y=1;$
$8*1(1,4*1+13,6*1)+13*1(0,8*1-0,6*1)=8*15+13*0,2=$
$=120+2,6=122,6$