Question

$2 x^{2} -6x+4 leq 0$

Answer 1

$2 x^{2} -6x+4 leq 0 \ x^2 -3x+2 leq 0 \ x^2 -3x+2=0 \ D=9-8=1 \ x_1= frac{3+1}{2}=2 \ x_2= frac{3-1}{2}=1 \ xin[1; 2]$
Ответ: 1<=x<=2