Question

Сократите дробь.

3x^2-10x+3 / x^2-3x

Answer 1

$frac{3x^2-10x+3}{x^2-3x} = frac{3x^2-9x-x+3}{x^2-3x} = frac{3x(x-3)-(x-3)}{x^2-3x} = frac{(x-3)(3x-1)}{x(x-3)} =frac{3x-1}{x}$

Answer 2

$\frac{3x^2-10x+3}{x^2-3x}=frac{3x^2-x-9x+3}{x(x-3)}=frac{x(3x-1)-3(3x-1)}{x(x-3)}=frac{(3x-1)(x-3)}{x(x-3)}=frac{3x-1}{x} \. \xneq0 wedge xneq3$