Question

-2sinx+5sin2x=0
Помогите решить!

Answer 1

$-2sinx + 5sin2x = 0 \ \ 10sinxcosx - 2sinx = 0 \ \ 5sinxcosx - sinx = 0 \ \ sinx(5cosx - 1) = 0 \ \ sinx = 0 \ \ boxed{x = pi n, n in Z} \ \ 5cosx = 1 \ \ cosx = dfrac{1}{5} \ \ boxed{x = pm arccos dfrac{1}{5} + 2 pi k, k in Z}$

Answer 2

Спасибо большое