Предмет: Математика, автор: Надюлик

решите неравенство
2sinx<-1

Ответы

Автор ответа: aasassin
0

2sinx+1=0

2sinx=-1

sinx=-1/2

x=(-1)^(k+1)(arcsin(-1/2)+Пк,к э Z

x=(-1)^(k+1)* (pi/6)+Пк,к э Z

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