Question

найдите значение производной функции y=3tgx в точке X0=-п/4

Answer 1

$y'(x)= frac{3}{Cos^{2}x}$
$y'(x_{0} )= frac{3}{Cos^{2}(- frac{ pi }{4} )} = frac{3}{ frac{1}{2} } =6$

Answer 2

y' = 3*(tgx)' = 3/cos^2x

y'( - pi/4) = 3/cos^2(-pi/4) = 3/cos^2(pi/4) = 3/0,5 = 6