Question

8х^2-6>7-4х решите подробно

Answer 1

$8x^2-6>7-4x \ 8x^2+4x-13>0 \ 8x^2+4x-13=0 \ D_1=4+104=108 \ x_1= frac{-2- sqrt{108} }{8} \ x_2= frac{-2+ sqrt{108} }{8} \ xin (-infty; frac{-2- sqrt{108} }{8} )cup ( frac{-2+ sqrt{108} }{8} ; +infty)$

Answer 2

д= 432