Question

3х(5-6х)<7х(1-х) помогите решить

 

Answer 1

$3x(5-6x)<7x(1-x) \ 15x-18x^2<7x-7x^2 \ 11x^2-8x>0 \ 11x^2-8x=0 \ x_1=0 \ x_2= frac{8}{11} \ xin(-infty; 0)cup(frac{8}{11} ;+infty)$