Question

x^3-6x^2-4x+24=0 решите уравнение

Answer 1

$x^3-6x^2-4x+24=0 \ x^2(x-6)-4(x-6)=0 \ (x-6)(x-2)(x+2)=0 \ x-6=0 \ x_1=6 \ x-2=0 \ x_2=2 \ x+2=0 \ x_3=-2$
Ответ: -2, 2 и 6

Answer 2

x^3-6x^2-4x+24=0
x^2(x-6)-4(x-6)=0
(x-6)(x-2)(x+2)=0
x=6 x=2 x=-2